Class 9 | Chapter 7 | Triangles | Example 1
Example 1: In Fig. 7.8, OA = OB and OD = OC. Show that (i) ∆ AOD ≅ ∆ BOC and (ii) AD || BC. Class 9 | Home Example 2
Read MoreExample 1: In Fig. 7.8, OA = OB and OD = OC. Show that (i) ∆ AOD ≅ ∆ BOC and (ii) AD || BC. Class 9 | Home Example 2
Read MoreTheorem 7.8: The sum of any two sides of a triangle is greater than the third side. Theorem 7.7 Class 9 | Home
Read MoreTheorem 7.7: In any triangle, the side opposite to the larger (greater) angle is longer. Theorem 7.6 Theorem 7.8
Read MoreTheorem 7.6: If two sides of a triangle are unequal, the angle opposite to the longer side is larger (or greater). Theorem 7.5 Theorem 7.7
Read MoreTheorem 7.5: (RHS congruence rule) : If in two right triangles the hypotenuse and one side of one triangle are equal to the hypotenuse and one side of the other triangle, then the two triangles are congruent. Theorem 7.4 Theorem…
Read MoreTheorem 7.4: (SSS congruence rule) If three sides of one triangle are equal to the three sides of another triangle, then the two triangles are congruent. Theorem 7.3 Theorem 7.5
Read MoreTheorem 7.3: The sides opposite to equal angles of a triangle are equal Theorem 7.2 Theorem 7.4
Read MoreTheorem 7.2: Angles opposite to equal sides of an isosceles triangle are equal. Theorem 7.1 Theorem 7.3 Prerequisite It is quite easy to prove this theorem and it’s been proved by two different ways in the above tutorial: Using angle…
Read MoreTheorem 7.1: (ASA congruence rule) Two triangles are congruent if two angles and the included side of one triangle are equal to two angles and the included side of other triangle. Home Theorem 7.2
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