Class 9 | Chapter 8 | Quadrilaterals | Exercise 8.2 | Question 6
Question 6: Show that the line segments joining the mid-points of the opposite sides of a quadrilateral bisect each other. Question 5 Question 7
Read MoreQuestion 6: Show that the line segments joining the mid-points of the opposite sides of a quadrilateral bisect each other. Question 5 Question 7
Read MoreQuestion 5: In a parallelogram ABCD, E and F are the mid-points of sides AB and CD respectively (see Fig. 8.31). Show that the line segments AF and EC trisect the diagonal BD. Question 4 Question 6
Read MoreQuestion 4: ABCD is a trapezium in which AB || DC, BD is a diagonal and E is the mid-point of AD. A line is drawn through E parallel to AB intersecting BC at F (see Fig. 8.30). Show that…
Read MoreQuestion 3: ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rhombus. Question 2 Question 4
Read MoreQuestion 2: ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rectangle. Question 1 Question 3
Read MoreQuestion 1: ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA (see Fig 8.29). AC is a diagonal. Show that : (i) SR || AC and SR =…
Read MoreQuestion 12: ABCD is a trapezium in which AB || CD and AD = BC (see Fig. 8.23). Show that (i) ∠A = ∠B (ii) ∠C = ∠D (iii) △ABC ≅ △BAD (iv) diagonal AC = diagonal BD [Hint: Extend…
Read MoreQuestion 11: In △ABC and △DEF, AB = DE, AB || DE, BC = EF and BC || EF. Vertices A, B and C are joined to vertices D, E and F respectively (see Fig. 8.22). Show that (i) quadrilateral…
Read MoreQuestion 10: ABCD is a parallelogram and AP and CQ are perpendiculars from vertices A and C on diagonal BD (see Fig. 8.21). Show that (i) △APB ≅ △CQD (ii) AP = CQ Question 9 Question 11
Read MoreQuestion 9: In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP = BQ (see Fig. 8.20). Show that: (i) △APD ≅ △CQB (ii) AP = CQ (iii) △AQB ≅ △CPD (iv) AQ =…
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